Calculating Lande g-Factor for 3S1, 3P0, 3P1, 3P2 States

  • Thread starter Thread starter neu
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the Lande g-factor for the quantum states 3S1, 3P0, 3P1, and 3P2. Participants clarify that the g-factor is derived using the formula involving total angular momentum (J), orbital angular momentum (L), and spin angular momentum (S). The confusion arises from the relationship J = L ± S, where the values of J can range from |L-S| to |L+S|. Specific examples, such as calculating g for Eu(3+) with outermost orbitals 4f6, are also discussed.

PREREQUISITES
  • Understanding of quantum mechanics, specifically angular momentum and vector addition.
  • Familiarity with the Lande g-factor formula and its application in the Zeeman effect.
  • Knowledge of electron configurations and how they relate to quantum states.
  • Basic proficiency in interpreting quantum state notations (e.g., 3S1, 3P0).
NEXT STEPS
  • Study the derivation of the Lande g-factor formula in quantum mechanics.
  • Learn about the Zeeman effect and its implications in spectroscopy.
  • Explore the concept of total angular momentum in quantum systems.
  • Investigate electron configurations and their impact on magnetic properties of elements.
USEFUL FOR

Students and professionals in physics, particularly those specializing in quantum mechanics, atomic physics, or spectroscopy, will benefit from this discussion.

neu
Messages
228
Reaction score
3
Im getting very confused about how to calculate the lande g-factor for the 3S1, 3P0, 3P1, and 3P2 states

I know its equal to

http://www.pha.jhu.edu/~rt19/hydro/img208.gif

but if i have state 3P0 where S=1 as 2S+1 = 3 and L=P=1 and J=0, but J=L+S which isn't =1?

I've read myself into a hole can someone help us out?


I should say the g-value is used in the zeeman effect. Gives the energy shift as ratio of bohr magneton

http://www.pha.jhu.edu/~rt19/hydro/img207.gif
 
Last edited by a moderator:
Physics news on Phys.org
neu said:
Im getting very confused about how to calculate the lande g-factor for the 3S1, 3P0, 3P1, and 3P2 states

I know its equal to

http://content.answers.com/main/content/wp/en/math/b/6/e/b6e998bf64dfdc8346b1937dac439df5.png

but if i have state 3P0 where S=1 as 2S+1 = 3 and L=P=1 and J=0, but J=L+S which isn't =1?

I've read myself into a hole can someone help us out?
J = L±S yes?
 
Last edited by a moderator:
Why would you need to calculate it if there is no electron at that energy level? Guess I'm missing something.
 
neu said:
Im getting very confused about how to calculate the lande g-factor for the 3S1, 3P0, 3P1, and 3P2 states

I know its equal to

http://www.pha.jhu.edu/~rt19/hydro/img208.gif

but if i have state 3P0 where S=1 as 2S+1 = 3 and L=P=1 and J=0, but J=L+S which isn't =1?

I've read myself into a hole can someone help us out?

Just plug in the values of S,L and J.

Your problem does not seem to be in finding g but in vector addition in QM. Recall that in QM, writing {\vec J } = {\vec L } + {\vec S} means that J will range from |L-S| to |L+S| in steps of 1. So, if S=1 and L=1, J could take any value between |1-1| and |1+1| so J may be equal to 0, 1 or 2. Your 3P0, 3P1 and 3P2 states correspond to those three possible values of J.

Hope this makes helps.

Patrick
 
Last edited by a moderator:
Thats exactly the clarity i needed thankyou
 
I'm stuck with calculating g and p for Eu(3+).

The outtermost orbitals in Eu is 4f7 5s2 5p6 6s2. Eu(3+) has 4f6 as the last orbital.

Thus, S = 3, L = 3 and J = 0 since J = L - S here.

How do I calculate g (using the formula given above) and then p. (p = g[S(S+1)]).

The experimental value for p = 3.4 and I read that g must be 2 in this case.

I am at a loss how to arrive at this result.

Can anyone help?
 
:cry::confused::rolleyes:

Someone please help . . .
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
13K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
6K