Calculating Magnetic Field in a Circular Circuit with Varying Resistivity

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SUMMARY

The discussion focuses on calculating the magnetic field at the center of a circular circuit with varying resistivity. The circuit consists of two resistances, R1 with a resistivity of 4Ω-m and R2 with a resistivity of 2Ω-m, arranged in a circle of radius 1 m, powered by a 10∏ volt battery. The angle between points A and B is 60°. The initial attempt to calculate the magnetic field using the formula B = μiθ/4∏r was incorrect due to not accounting for the differing currents in each segment of the circuit.

PREREQUISITES
  • Understanding of magnetic fields and their calculations
  • Familiarity with Ohm's Law and circuit analysis
  • Knowledge of resistivity and its impact on current
  • Proficiency in using the formula B = μiθ/4∏r
NEXT STEPS
  • Calculate the current in each segment of the circular circuit
  • Learn about the impact of varying resistivity on circuit behavior
  • Study the derivation and application of the Biot-Savart Law
  • Explore advanced magnetic field calculations in non-uniform circuits
USEFUL FOR

Students studying electromagnetism, electrical engineers, and anyone involved in circuit design and analysis, particularly in contexts involving magnetic fields and resistivity variations.

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Homework Statement


In the ATTACHMENT is the given circuit. Which contains two resistance
R1 and R2 in form of circle of radius r = 1 m with a battery
having e.m.f. V = 10∏ volt. Upper resistance is having
resistivity = 4Ω-m & lower resistance having resistivity =
2Ω-m. Angle between two points A and B is 60°. (wires have
same cross section A1 = A2 = 2 cm2)
Find magnitude of magnetic field at centre.

The attempt at a solution
I tried it using the formula B = μiθ/4∏r. BUT THE ANSWER IS NOT COMING CORRECT.

Screenshot from 2013-10-19 08:20:55.png
 
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BUT THE ANSWER IS NOT COMING CORRECT.
Please don't write in caps.
What did you get for the currents in both parts of the circle?
Which field strength did you get, and do you know the correct answer?
Note that the currents will be different in the two sides. And you have to take their length into account.
 

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