Calculating Max. Distance of Block on Turntable Rotating at 33 1/3 rev/min

AI Thread Summary
To determine the maximum distance a brass block can be placed from the axis of a turntable rotating at 33 1/3 rev/min without sliding off, the equation mω²R ≤ µmg is used, where µ is the coefficient of friction. Rearranging this gives R ≤ µg/ω². Given µ = 0.17 and the angular velocity ω can be calculated from the rotation speed, the maximum radius R can be computed. The solution confirms that this approach is correct for finding the maximum distance. The discussion focuses on applying physics principles to solve the problem effectively.
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The coefficient of friction between a certain brass block and a large revolving turntable is µ = 0.17. How far from the axis of rotation can the block be placed before it slides off the turntable if it is rotating at 33 1/3 rev/min?

i was wondering was this the equation to solve this question?
m ω^2 R <= µ m g

R <= µ g / ω^2



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