Calculating Max Speed of 0.3 kg Mass on Horizontal Spring

AI Thread Summary
To calculate the maximum speed of a 0.3 kg mass attached to a spring with a spring constant of 32 N/m stretched 0.2 m, the correct approach involves using energy conservation principles. The potential energy stored in the spring when stretched is converted to kinetic energy at maximum speed. The formula for maximum speed is derived from equating the potential energy (1/2 k x^2) to kinetic energy (1/2 m v^2). The stretch of the spring at maximum speed is zero, as it returns to its equilibrium position. The discussion highlights the importance of considering energy conservation and the spring's behavior during motion.
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Homework Statement



If a mass of 0.3 kg is attached to a horizontal spring system with a spring constant of 32 N/m^2 is stretched 0.2 m from its relaxed length, what is the maximum speed the mass will attain when released from this position?



The Attempt at a Solution


i thought all you end up with is Vf=squareroot of k/m(xi^2-xf^2) but it is wrong.
 
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When the mass is at its maximum speed, what will be the stretch of the spring?
 
x_i=?\mbox{ and }x_f=?{ },{ }\mbox{how do you think?}
\mbox{does the statement is complete? frictional force?}
 
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