Calculating Mean, Median or Mode for Ace-Inhibitor Patients

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SUMMARY

The discussion centers on calculating the central tendency (mean, median, mode) for ace-inhibitor patients based on provided measurements. The dataset includes values such as 0.0, 12.5, 13.6, and others, revealing a skewed distribution. Participants agree that the median (12.5) is the most appropriate measure due to the presence of outliers (0.0 values), which significantly affect the mean (9.8). The consensus is that the median provides a more accurate representation of the central tendency in this scenario.

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Homework Statement



You are asked to estimate of the most common level of a ace-inhibitor taken by patients who take the drug. Give your best estimate of central tendency.

These are the measurements
0.0 12.5 13.6 14.5 12.0 13.2
0.0 0.0 13.1 14.2 12.5 12.2


Homework Equations



Mean, Median or mode

The Attempt at a Solution



I know it is definitely not the mode. I am stuck between the mean and the median. The median should be used when skewed data is present because it is less sensitive to outliers. This data is skewed because the median (12.5) is greater than the mean (9.8)

However, should those patients with measurements of be considered outliers because three of them had this measurement.

Help please
 
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Yes, those "0"s are definitely outliers!
 
I agree that the median would be the best estimate of central tendency, but the phrase "You are asked to estimate of the most common level" stick out at me. That wording isn't often used as a description of what either the mean or median provide.
 

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