Calculating Mechanical Energy Lost on Slide for 25.0 kg Child

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SUMMARY

The discussion focuses on calculating the mechanical energy lost due to friction for a 25.0 kg child sliding down a playground slide from a height of 19.00 m to 6.00 m while reaching a speed of 9.10 m/s. The key equations used include potential energy (Pe = mgh) and kinetic energy (Ke = 0.5mv²). The solution involves determining the difference between the initial potential energy and the sum of kinetic energy at the lower height, confirming that energy conservation principles apply. The final calculation reveals the energy lost due to friction.

PREREQUISITES
  • Understanding of potential energy (Pe = mgh)
  • Knowledge of kinetic energy (Ke = 0.5mv²)
  • Familiarity with the conservation of energy principle
  • Basic algebra for solving equations
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn about energy loss due to friction in real-world applications
  • Explore advanced topics in dynamics and energy transformations
  • Practice problems involving energy calculations in various scenarios
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their teaching of energy concepts in practical situations.

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Homework Statement


A 25.0 kg child slides down a long slide in a playground. She starts from rest at a height h1 of 19.00 m. When she is partway down the slide, at a height h2 of 6.00 m, she is moving at a speed of 9.10 m/s. Calculate the mechanical energy lost due to friction (as heat, etc.).
http://schubert.tmcc.edu/enc/81/eb6d48e17d7ac6da6bcc155569197bc91de6184725281bb9c7a8766b6518bc88bed47674ecdc931377509dc0eb7e26d7db2890f53e24b7f2d99a7111ddfa3536dc35b6f684771013136fcdf8150697ebc0e216fcb068cc8874c532077ab9fdb93e14da5cdf2b76ec.gif


Homework Equations





The Attempt at a Solution


This question has something to do with change in potential energy and kinetic energy, but i am not sure where to go.
 
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You are not showing any attempt. Before attempting the problems of this type, you must have gone through conservation of energy in freely falling body. Why don't you apply that?
 
I have found potential energy at the top of the system (Pe=mgy). I have also found kinetic energy at the lower point (Ke=.5mv^2). It would make sense to take the difference, but I have already tried this method.
 
Without friction, total energy is conserved. Which means the sum of your kinetic and potential energies should be equal at any two points taken. Are you sure you're including all forms of energy for the second point?
 
I was able to find the answer! Thanks for the tips!
 

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