Calculating Momentum for Egg Drop Project

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SUMMARY

This discussion focuses on calculating the momentum of a standard egg weighing 0.05 kg dropped from heights of 1, 2, and 3 meters. To determine momentum, the formula used is momentum (p) = mass (m) × velocity (v). Given that air resistance is negligible, standard vertical motion equations can be applied to calculate the velocity just before impact for each height, ensuring the mass of the egg is accurately noted as 50 grams.

PREREQUISITES
  • Understanding of basic physics concepts, particularly momentum and velocity.
  • Familiarity with standard vertical motion equations.
  • Knowledge of mass measurement, specifically in grams.
  • Ability to perform calculations involving multiplication and square roots.
NEXT STEPS
  • Research the standard vertical motion equations for free-fall calculations.
  • Learn how to calculate velocity using the formula v = √(2gh), where g is the acceleration due to gravity.
  • Explore examples of momentum calculations in physics, particularly for objects in free fall.
  • Investigate the effects of air resistance on momentum for different objects.
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Students studying physics, educators teaching momentum concepts, and anyone involved in practical applications of physics in experiments or projects.

paapostolas
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Homework Statement


i need to make sample calculations of momentum using the mass of a standard egg (.05kg) dropped from 1 2 and 3 meter heights. but i have no clue how to do this
 
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paapostolas said:

Homework Statement


i need to make sample calculations of momentum using the mass of a standard egg (.05kg) dropped from 1 2 and 3 meter heights. but i have no clue how to do this

From those heights, air resistance should be negligible, so use standard vetical motion equations/formulae to calculate the velocity.

Momentum is merely mv and you know the mass - make sure you are using 50g eggs and not 45g, 55g, 60g, or 65g which are other common sizes sold here.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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