Calculating Neutral Current in Three-Phase Unbalanced Systems

Click For Summary
SUMMARY

This discussion focuses on calculating neutral current in three-phase unbalanced systems, specifically in a 3-phase, 4-wire wye configuration. For balanced loads, the vector diagram is straightforward, while unbalanced loads require a different vector analysis approach. The absence of one phase, such as the C Phase, indicates an unbalanced condition that significantly affects neutral current calculations. Understanding vector analysis is essential for accurately determining these currents in practical applications.

PREREQUISITES
  • Three-phase power systems
  • Vector analysis fundamentals
  • Wye and delta configurations
  • Neutral current calculations
NEXT STEPS
  • Study neutral current calculation methods in unbalanced three-phase systems
  • Explore vector analysis techniques for electrical engineering
  • Learn about the impact of load imbalance on neutral current
  • Investigate simulation tools for three-phase power systems
USEFUL FOR

Electrical engineers, power system analysts, and students studying three-phase systems will benefit from this discussion, particularly those focusing on load balancing and neutral current calculations.

Miki Abe
Messages
5
Reaction score
0
How to culculate neutral current in three phase system with unbalance load?
 
Engineering news on Phys.org
For balanced loading on a 3-phase, 4-wire wye system like this,

810ecmBTBfig1.jpg

the vector diagram would looks like this:

810ecmBTBfig2.jpg


Now follow this Basics of Vector Analysis.

Now for unbalanced loading on a 3-phase, say like this,

811ecmBTBfig1.jpg


the vector diagram would look like this, since there's no C Phase (definitely unbalanced :D):

811ecmBTBfig2.jpg


Now follow this Vector Analysis.

Good Luck
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

Replies
4
Views
10K
Replies
35
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
14
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K