Calculating Noise Power, SNR, and Bit Error Probability

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To calculate noise power, signal-to-noise ratio (SNR), and bit error probability, start with the average power derived from voltage and resistance values. The noise figure is a useful concept, and you can calculate power using the formula P = I_RMS * V_RMS or P = V_RMS^2 / R. For accurate SNR calculations, detailed information about the noise source is crucial, especially if it involves electronic component noise. Noise power can be determined as the variance of the signal, while SNR is calculated as the ratio of signal power to noise power. The bit error probability can be estimated using the formula PE = 0.5erfc(V/2 * variance * sqrt(2)).
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I have values of time, and volts of a noise signal.

I am trying to determine the noise power, signal to power ratio and bit error probability.

How would I go about doing this?

Thanks.
 
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You start out with average power if you have the time and voltage.

Usually people use noise figure:

http://en.wikipedia.org/wiki/Noise_figure

Is that what you want? If so and you still have question, come back.
 
Ah ok, thank you.

Is this the method for volt and time values obtained from scope? Currently I have the data in excel. I will read into noise figure.

If you have any particular formulas that could give me a start that would be great.
 
As power is average, you need to take the average of the volt to the resistance or if you know the current you can calculate as

P= I_{RMS}V_{RMS}=\frac {V_{RMS}^2} R

You have to use your data to find the RMS. Someone might want to come in about \frac 1 2. I just don't remember when to put the half in or not.

You calculate the power of the signal, This is the easy part. The trick is knowing your noise source. You need to give a lot more information about the noise before you can get the signal to noise ratio. If it is electronic component noise, then you need to give your circuit and calculate from there.
 
Yea I have come across many formulas like this, however the problem is I have values for only the time, and volts.
 
Never mind. The Noise power is the variance (S.D. ^2), and the SNR is the Signal Power/Noise Power. Signal Power is A^2/2.
PE = 0.5erfc(V/2*variance*sqrt(2))

Thanks anyways.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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