Calculating Nonconservative Energy Loss in Pumped-Storage Reservoirs

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To calculate the nonconservative energy loss in a pumped-storage reservoir, first determine the gravitational potential energy using the height of 136 m and the mass of 9.0×10^9 kg, which results in a significant initial energy value. The power plant generates 346 MW over a period of 6.9 hours, translating to a specific amount of energy produced. By comparing the energy generated to the initial gravitational potential energy, the fraction of energy lost to nonconservative forces can be calculated. This fraction represents the efficiency of the energy conversion process in the pumped-storage system. Understanding these calculations is crucial for optimizing energy storage and generation in such systems.
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new problem!

A pumped-storage reservoir sits 136 m above its generating station and holds 9.0×10^9 kg of water. The power plant generates 346 MW of electric power while draining the reservoir over an 6.9 h period.
What fraction of the initial potential energy is lost to nonconservative forces (i.e., does not emerge as electricity)?

could you please guys help me with that? I gave up with that
I need that in hour guys please please.
 
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136 m above its generating station and holds 9.0×10^9 kg. so what is the gravitational potential energy?

346 MW over an 6.9 h... what is the energy generated here?

so how much energy is lost?

what is the fraction of this energy to the original gravitational potential energy.
 
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