Calculating Orbit Parameters Given Perigee Velocity and Period

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A satellite in Earth orbit with a perigee velocity of 8 km/s and a period of 2 hours requires calculations for its orbit parameters, including altitude at perigee. The vis viva equation is suggested for more accurate results, as the initial equation provided is only valid for circular orbits. The discussion highlights confusion regarding the semi-major axis and eccentricity, with incorrect calculations leading to negative eccentricity values. Clarifications emphasize that specific angular momentum and semi-major axis are distinct, requiring different units. Accurate calculations are crucial for determining the satellite's orbital characteristics.
dorai007
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Hi guys,

i can't seem to find the answer .

A satellite in Earth orbit has a perigee velocity of 8 km=s and period of 2 hours. From this information,
determine all the orbit parameters that you can. From those parameters, determine its altitude at perigee
--------------------------------------------------------

my vp=8km/sec
T=7200sec
Vp=sqrt(GM/r)---is this right and is r =rp?





how do i calculate my semi major axis? is it from kepler's 3rd law? I am stuck at finding rp and eccenctricity and I've been going at this for hours without proper examples in books/online.

Someone please help!
 
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dorai007 said:
Vp=sqrt(GM/r)---is this right and is r =rp?
That equation is valid only for circular orbits. The vis viva equation provides a more general answer:

\frac{v^2}{GM} = \frac 2 r - \frac 1 a
how do i calculate my semi major axis? is it from kepler's 3rd law?
Correct. So show some work so we can help you out a bit.
 
but if its vis viva will my eccentricity value be more than 0.2..thats the value I am getting, this is how I am doing my calculations

1) equation 1 : mag(h)=mag(rp)*mag(v)
equation 2: mag(rp)= [mag(h)^2/GM]/(1+ecos(v) - trajectory eqn
equation 3: T= 2phi/sqrt(GM) * (mag(h))^3/2

i am to solve 3 unknowns mag(h),rp and e by simultaneous eqns by substituting all the equations into one another.

ive done it a couple of times, either I am getting a negative value for e(-0.1) which shldnt be the case.

But my qn here is. if v=8000m/sec what is mag(v)? and in this case will a=mag(h) ?
 
dorai007 said:
but if its vis viva will my eccentricity value be more than 0.2..thats the value I am getting,
Then you are doing it wrong. The eccentricity is less than 0.2. Show your work.

this is how I am doing my calculations

1) equation 1 : mag(h)=mag(rp)*mag(v)
equation 2: mag(rp)= [mag(h)^2/GM]/(1+ecos(v) - trajectory eqn
equation 3: T= 2phi/sqrt(GM) * (mag(h))^3/2
Your equation 1 is only valid for circular orbits, and for elliptical orbits at perifocus and apofocus. (Since the given data point is perigee, this equation is okay here.) Your equation 3 however is only valid for circular orbits.

Try finding a formula that relates semi-major axis (rather than specific angular momentum) to the period.

But my qn here is. if v=8000m/sec what is mag(v)? and in this case will a=mag(h) ?
The magnitude of the velocity vector is of course 8000m/s. As far as a=mag(h), no. Look at the units. Specific angular momentum(h) has units of length2/time. Semi-major axis (a) has units of length.
 
UC Berkely, December 16, 2025 https://news.berkeley.edu/2025/12/16/whats-powering-these-mysterious-bright-blue-cosmic-flashes-astronomers-find-a-clue/ AT 2024wpp, a luminous fast blue optical transient, or LFBOT, is the bright blue spot at the upper right edge of its host galaxy, which is 1.1 billion light-years from Earth in (or near) a galaxy far, far away. Such objects are very bright (obiously) and very energetic. The article indicates that AT 2024wpp had a peak luminosity of 2-4 x...

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