Calculating pH using Ka: Equal Concentrations of HB and B-

  • Thread starter Thread starter jpd5184
  • Start date Start date
  • Tags Tags
    Ph
AI Thread Summary
To calculate the pH of a solution with equal concentrations of the weak acid HB and its conjugate base B-, the Henderson-Hasselbalch equation is applicable. Given the acid dissociation constant (Ka) of 5.293 x 10^-6, the pH can be determined by using the relationship pH = pKa + log([B-]/[HB]). Since the concentrations of HB and B- are equal, the log term becomes zero, simplifying the calculation to pH = pKa. The pKa can be calculated as -log(5.293 x 10^-6), leading to the final pH value.
jpd5184
Messages
76
Reaction score
0

Homework Statement



ka= 5.293 x 10^-6

using Ka, calculate the ph of a solution that contains equal concentrations of HB and B-.


Homework Equations



ph = -log[H+]

The Attempt at a Solution



im guessing that HB is the acid and B- is the base
 
Physics news on Phys.org
Last edited by a moderator:
thanks
 
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top