Calculating Potential Difference in a Uniform Electric Field

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Homework Help Overview

The discussion revolves around calculating the potential difference in a uniform electric field defined by the vector E = (20,000 i - 50,000 j) V/m, specifically between two points at yi = -5 cm and yf = 5 cm.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration process for calculating potential difference, with one participant attempting to apply the integral incorrectly. There is a suggestion to treat the electric field as a constant due to its uniformity, leading to a simpler calculation. Another participant expresses confusion about the sign in their calculations.

Discussion Status

The discussion is ongoing, with participants providing insights into the integration method and questioning the correctness of their calculations. Some guidance has been offered regarding the treatment of the electric field as constant, but no consensus has been reached on the correct approach or solution.

Contextual Notes

Participants mention constraints such as the need to check signs in their calculations and the pressure of having limited attempts left in a homework system.

aliaze1
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Homework Statement



What is the potential difference between yi= -5cm and yf=5cm in the uniform electric field E = ( 20,000{ i } - 50,000 { j } )V/m?

Homework Equations



∆V = V(sf) - V(si) = -∫ Es ds

with the limits of the integral being sf and si

The Attempt at a Solution



I tried doing the integral, resulting in (E2)/2, and then multiplying proceding as so:

E= √ (200002 + 500002) = 53851.64807
(E2)/2 = 14500000 = x
x |0.05,-0.05 = -{x(0.05) - x(-0.05)} = -{2[x(0.05)]} = -1450000 = incorrect

any help?

thanks!
 
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I think you're taking the integral as if it were E dE instead of ds (Compare with the case where if it were the integral of x dx, then the integral is x^2/2). E is a constant since it is "uniform", so you can treat it as a constant and pull it out of the integral. If you're only dealing with one dimension (along y), then the integral of E ds simplifies to E(Sf - Si).
 
Anadyne said:
I think you're taking the integral as if it were E dE instead of ds (Compare with the case where if it were the integral of x dx, then the integral is x^2/2). E is a constant since it is "uniform", so you can treat it as a constant and pull it out of the integral. If you're only dealing with one dimension (along y), then the integral of E ds simplifies to E(Sf - Si).

aaahh lol nice...yea that was my mistake...lol whenever i see the integral sign i jump to conclusions without looking at the second part

thanks!
 
well actually...i tried that and it didn't work:

E = 53851.64807

Sf-Si = 0.05 - (-0.05) = 0.1

E * (Sf-Si) = 53851.64807 * 0.1 = 5385.164807 = Incorrect :(

Any help?

Thanks!
 
I have only one attempt left. I noticed that I didn't put the negative sign there, but the computer would tell me to 'check your signs' if this was a sign issue...so i assume it isn't
 
any help?
 

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