Calculating Power from rain flow

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SUMMARY

The discussion focuses on calculating the potential power harnessed from rainwater flowing out of downspouts, specifically using a mean rainfall of 600 mm per year and a height of 10 m. The calculation yields a power output of 0.47 Watts, leading to an annual extraction of approximately 170 Watt-days, assuming continuous rainfall. The user is advised that the average rainfall should be based on rainy days rather than the annual average, which significantly impacts the power output calculation.

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Homework Statement



As we have seen, energy can be extracted from moving water. When it rains, water that lands on roofs is collected in gutters and carried to the ground via downspouts. In a typical heavy rain in your city, how much power could be harnessed from the rain flowing out of your downspouts? How much power could you extract averaged over the course of the entire year?

Homework Equations





The Attempt at a Solution


Mean rainfall in this area: 600 mm per year = 0.6 m/year
Height: 10 m
Q: (250 m2)(0.6m/year)/ (3.15 × 107s/y) = 0.000004761 m3/s
Power Generated
η= efficiency= assume its 1
ρ= 1000kg/m3
g= 9.80 m/s2
P =ηρghQ = (0.000004761 m3/s) (1)(1000kg/m3) (9.80 m/s2)(10m)
P= 0.47 Watts
Year: 0.47 Watts x 365 days= 170 watts
We could extract about 170 watts over the course of the year assuming it rains everyday. This
calculation assumes that η is100% efficient and there is no loss due to evaporation..
If it only rains half the year then we would extract 170 watts/ 2= 85.2 Watts.


I don't know what I did. Please help me! :)

 
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unknown1991 said:
Year: 0.47 Watts x 365 days= 170 watts
0.47 Watts x 365 days= 170 Watt-days. Convert that to Joules, or kWh.
assuming it rains everyday
You used the average rainfall over a year, not the average rainfall on those days when it rains.
 

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