Calculating Power Supplied by CS and VS Sources

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SUMMARY

The discussion focuses on calculating the power supplied by a current source (CS) and a voltage source (VS) in a circuit. The current source provides 2A directed downwards, while the voltage source is set at 12V. The power supplied by the voltage source is confirmed to be 24W, and the power supplied by the current source is -24W, indicating that it absorbs power. The calculations utilize the formula P=Vi, confirming the initial instincts of the poster.

PREREQUISITES
  • Understanding of electrical circuit concepts such as current sources and voltage sources.
  • Familiarity with Ohm's Law (V=IR).
  • Knowledge of Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL).
  • Ability to apply power formulas (P=Vi, P=i²R, P=V²/R).
NEXT STEPS
  • Study the application of Kirchhoff's Laws in complex circuits.
  • Learn about power calculations in AC circuits.
  • Explore the implications of negative power in circuit analysis.
  • Investigate the role of passive and active components in power supply.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing power in electrical circuits will benefit from this discussion.

Noclue134
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Homework Statement


|----------|
|+ |+
CS VS
|- |-
|----------|

The current source is pointed downwards and is 2A while the VS is 12V
They are asking for the power supplied by each source.

Homework Equations


V=ir
KCL
KVL
P=Vi,i^2R,V^2/R

The Attempt at a Solution


I'm not sure how to begin this problem. My initial instincts tells me to simply use P=Vi so that the power supplied by the VS is 24W while the CS is -24W but I'm not sure if this is correct.

Any help would be appreciated, thanks in advance.

Edit: VS in the picture should be on the far right side of the "circuit"
 
Last edited:
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Noclue134 said:

Homework Statement


|----------|
|+ |+
CS VS
|- |-
|----------|

The current source is pointed downwards and is 2A while the VS is 12V
They are asking for the power supplied by each source.

Homework Equations


V=ir
KCL
KVL
P=Vi,i^2R,V^2/R


The Attempt at a Solution


I'm not sure how to begin this problem. My initial instincts tells me to simply use P=Vi so that the power supplied by the VS is 24W while the CS is -24W but I'm not sure if this is correct.

Yes, it's correct.
 

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