Calculating Power Using Applied Force and Velocity: Quick Homework Question

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Homework Help Overview

The problem involves calculating the power exerted by an applied force on a block being pulled at a constant speed across a horizontal surface. The block's mass and the angle of the applied force are also provided.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relevance of mass in the calculation, with some suggesting it may not be necessary. There are attempts to apply the power formula using different values and trigonometric functions, leading to discrepancies in results.

Discussion Status

The discussion is ongoing, with participants exploring different calculations and questioning the accuracy of their results. Some guidance has been provided regarding the correct use of the speed value, but no consensus has been reached on the final answer.

Contextual Notes

There is a noted confusion regarding the speed value used in calculations, which has led to differing results among participants. The original poster expresses uncertainty about the role of mass in the problem.

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Homework Statement



A 100kg block is pulled at a constant speed of 5.0 m/s across a horizontal floor by an applied force off 122N directed 37 degrees above the horizontal. What is the rate at which the force does work on the block?

Homework Equations



I know here we will use the instantaneous power formula P=dW/dt or P=Fvcos

The Attempt at a Solution



well i drew the FBD and started plugging in numbers in my formula, its just I am not sure where the Mass falls into place here I know the answer is 4.9x10[tex]^{}2[/tex] watts but not sure where to go from here thanks
 
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In this problem mass is not needed.
 
well my answer just doesn't match up with the answer my teacher gave us and i don't know why... i did 122*5.7sin(37) and came up with 418.5W or 4.2X10^2 W
 
nelly42688 said:
well my answer just doesn't match up with the answer my teacher gave us and i don't know why... i did 122*5.7sin(37) and came up with 418.5W or 4.2X10^2 W
Your calculation is wrong.
122*5*cos(37) = ?
 
wow! the whole time i was using 5.7m/s instead of 5m/s careless mistake sorry to waste your time
 

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