Calculating pressure fromV1 to V2 with a polytropic exponent

Click For Summary

Homework Help Overview

The discussion revolves around calculating the pressure in a bicycle pump during an isentropic compression process. The initial and final volumes are provided, and the gas in question is air, with the polytropic exponent noted as equal to the specific heat ratio for air.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between pressure and volume in an adiabatic process, referencing the relevant equation. There are questions regarding the necessity of temperature in the calculations, and some participants express confusion about the application of the formula.

Discussion Status

Participants are exploring the implications of the assumptions made regarding the system, particularly concerning the constancy of the amount of air during compression. Some guidance has been offered regarding the use of the adiabatic process equation, but there remains uncertainty about the initial conditions and their impact on the calculations.

Contextual Notes

There is mention of hypothetical values and real-world measurements, indicating potential discrepancies in the assumptions made about the system. The discussion also highlights the importance of understanding the conditions under which the equations apply, particularly regarding the amount of air involved in the process.

metiz1
Messages
4
Reaction score
0

Homework Statement



I have a bicycle pump where I need to calculate the pressure in a certain volume. No heat is lost during compression so this is a isentropic system

initial volume is 0.3L
final volume is 0.0195
Gas is air
n=k


Homework Equations


I don't know, that's the problem. I recognise this as a fairly simple question but I just don't know


The Attempt at a Solution



non
 
Physics news on Phys.org
Welcome to PF, metiz1! :smile:

An adiabatic process (for an ideal gas) has [itex]P V^\gamma = constant[/itex], where [itex]\gamma = {7 \over 5}[/itex] for air (as a diatomic ideal gas).
Combined with the initial pressure as standard pressure, you can calculate the final pressure.
 
Thank you for your reply.

I can't say I really understand your reply though...Shouldn't I enter the initial temperature (lets say 20C, 293K) somewhere in the equation?
 
metiz1 said:
Thank you for your reply.

I can't say I really understand your reply though...Shouldn't I enter the initial temperature (lets say 20C, 293K) somewhere in the equation?

No, you don't need the temperature.

Let me rephrase:
[tex]P_{initial} (V_{initial})^{7 \over 5} = P_{final} (V_{final})^{7 \over 5}[/tex]

Solve for [itex]P_{final}[/itex].


You can find the formula for instance here:
http://en.wikipedia.org/wiki/Adiabatic_process
(Shouldn't it be in your notes or something? :confused:)
 
Thanks for your help! I had to use a hypotetical situation (n=1.4) for my calculations and see how the real word measurements stacked up...The n value I got was like 0.8...I dun goofed the measurement I think :P
 
Hmm, I just realized... you're talking about a pump.
I suppose that means the amount of air changes?
Kind of relevant, since the formula only works when the amount of air remains constant...
 
Yes you are right, however, in this situation I had to asume all the air was being compressed in a smaller volume withouth any air or heat escaping, so all is good.
 

Similar threads

  • · Replies 116 ·
4
Replies
116
Views
7K
Replies
12
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
49
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
8
Views
2K
Replies
2
Views
1K
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K