MHB Calculating Probability of Winning a Point on Serve in Tennis

JamesBwoii
Messages
71
Reaction score
0
Hi, I'm trying to make a tennis betting model but I'm struggling to get my head around how to calculate the probability of a player to win a point when serving. So:

How can I calculate the probability, p, of a player winning a point when serving given:

The percentage of first serves that the player gets in. (I'm not sure this is relevant/needed).

The percentage of first serve points won.

The percentage of second serve points won.

For example say a player gets 57.9% of first serves in, wins 70.4% of first serve points and 49.5% of second serve points how would I calculate p.

Thanks :D
 
Mathematics news on Phys.org
I think I've got it.

Is it:

Percentage of first serve in * percentage of first serve won + (1-percentage of first serve in) * percentage of second serve won.This seems about right, if you know about tennis it gives the probability of winning a service point of:

Djokovic - 69%
Isner - 73%
Ferrer - 63%
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top