Calculating Punch Through Force for Aluminum 7075

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SUMMARY

The calculation of punch through force for Aluminum 7075 involves using the formula P = (LTS)/2000, where P represents press tonnage, L is the circumference of the circular disc, T is the thickness of the material, and S is the ultimate tensile strength of Aluminum 7075. The ultimate tensile strength must be considered to determine the necessary force in tons to punch through the material. Additionally, understanding the failure mode—whether tensile, compressive, torsional, or shear—is crucial for accurate calculations.

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  • Understanding of ultimate tensile strength (UTS) of materials
  • Knowledge of basic mechanical engineering principles
  • Familiarity with the geometry of circular discs
  • Ability to perform unit conversions (e.g., psi to tons)
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  • Research the ultimate tensile strength of Aluminum 7075
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  • Explore mechanical engineering calculations for press tonnage
  • Investigate the effects of thickness and area on pressure calculations
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Mechanical engineers, materials scientists, and professionals involved in manufacturing processes that require precise calculations for punching or cutting through materials like Aluminum 7075.

Str8phaded22
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I am trying to figure out how to get the punch through force of an object. However, the data that I have pulled up have all contradicted each other.

Basically, How much force (in tons) is needed for an circular disc to be punched through Aluminum 7075.

What I have already came up with is:

P= (LTS)/2000

P=Press tonnage
L=circumference of circle
T=thickness
S=material strength in (ultimate tensile strength)


If anyone has any thoughts about this, could you please get back to me on this!

Thank you!
 
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Think about the "failure" mode of the material you're punching; is it tensile, compressive, torsional, shear, or what, and then pick a modulus.
 
Thanks!

Thank you Bystander,

It was ultimate tensile strength, for a certain aluminum.

Strength (psi) x Area = pressure(pounds)
 

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