- #1

raniero

- 42

- 0

The equation I used was: F = A x Ss

where F is the cutting force, A is the shear area (0.01 x 0.6) , and Ss is the shear strength.

Using this equation the cutting force would be ridiculously large, 420 kN.

Can someone please point me in the right direction ? Books, examples and explanations are appreciated

Thanks