Calculating Relative Motion Using Time and Distance Equations

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To solve the problem of calculating the ratio of the man's running speed to the sidewalk's speed, the key is to recognize that he travels the same distance in both directions. By setting up the equations for velocity as V(with) = length/2.5 and V(against) = length/8, one can express the distance traveled in both cases. Since the distances are equal, equating the two expressions allows for the determination of the ratio of speeds. The solution hinges on eliminating the unknown length of the sidewalk by using the equality of distances. Ultimately, this approach will yield the desired ratio of the man's running speed to the sidewalk's speed.
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A suspicious-looking man runs as fast as he can along a moving sidewalk from one end to the other, taking 2.50 s. Then security agents appear and the man runs as fast as he can back along the sidewalk to his starting point, taking 8.00 s. What is the ratio of the man's running speed to the sidewalk's speed? (running speed / sidewalk speed)

Thanks
 
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Where is your attempt at the solution?
 
I'm not sure how to go about it. I set up the velocities as V(with)=length/2.5 and V(against)=length/8, but I'm not sure what to do from there.
 
How do I work around the fact that i don't know the length of the sidewalk?
 
You know that both times he travels the same distance. What you need to do is find an expression that would give you the distance for run 1 and run 2. You can then equate them because you know the distance should be the same and you should be able to find the answer from there.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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