Calculating Relativistic Rocket Performance

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    Relativistic Rockets
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Discussion Overview

The discussion revolves around the relativistic rocket performance, specifically focusing on the relativistic version of the Tsiolkovsky rocket equation. Participants explore the implications of mass-energy conversion in high-speed propulsion systems, including the challenges of incorporating energy conversion into the rocket equation and the nature of exhaust in the context of relativistic speeds.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions how to account for mass converted to energy when calculating rocket performance, particularly when a significant portion of the fuel mass is not used as propellant.
  • Another participant emphasizes the importance of specific impulse, which relates to the momentum gained from fuel usage.
  • A participant shares their experience with MATLAB simulations, noting initial confusion with results but later confirming their understanding of the equation.
  • One participant raises a question about whether the rocket equation applies if the exhaust is in the form of radiation, specifically considering the feasibility of a self-fueled laser as a classical rocket.
  • Another participant provides information about the specific impulse of photon or laser exhaust, explaining its equivalence to the speed of light and its conversion to different units.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the incorporation of mass-energy conversion into the rocket equation and whether radiation can be treated as a classical rocket exhaust. Multiple competing views remain on these topics.

Contextual Notes

Participants have not resolved the assumptions regarding mass ratios in the context of energy conversion, nor have they clarified the implications of using radiation as exhaust in the relativistic framework.

trilex1
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Hello there

I've been looking at this page

http://en.wikipedia.org/wiki/Relativistic_rocket

at the relativistic version of Tsiolkovsky rocket equation, but something puzzles me


With chemical rockets, the mass that is being converted into energy is so tiny that almost
all fuel mass can be considered to end up as propellant, but when we are talking about relativistic speeds, the energy requirements are so high that a major portion of fuel would end up being converted to energy.

What puzzles me is how to incorporate this into this equation.

For example, if 80% of the rocket mass was fuel, and there was, say a fusion process, and the product was propellant with kinetic energy equal to matter that was converted into energy how would you incorporate this into the equation? Because now, not all of the fuel mass is propellant, and yet there was indeed a loss in ships mass (which was converted into kinetic energy)
Any ideas?

Perhaps my assumptions about the equation are wrong.
I assumed that the mass ratios are just reaction mass vs. total mass, and have nothing to do with that portion of mass that is converted into energy
 
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The wikipedia page you cite talks about this in some detail - have you looked at it closely?

What's important is (as the page says) the amount of momentum you get when you utilize one unit (say 1kg) of fuel. This is known as "specific impulse".
 
Now this is embarrassing

I did actually read the whole page, and entered everything into matlab, to get some nice curves out, and then started getting strange results, actually I was getting out complex numbers, lol, so I thought maybe I didn't understand the equation right, which is why I started this thread.

Either way, it works fine now after I double checked it

thanks

I hope this thread doesn't end up as useless
 
But just so this thread doesn't go to waste, I'm going to ask, this this equation still hold if your "exhaust" is in form of radiation?
In other words, can a self-fueled laser be a classical rocket.
I know radiation has momentum, but I'm just wondering if there is a catch
 
The specific impulse of a photon / laser exhaust is 1 in geometric (relativistic) units. In meters/second, it's just 'c'. You might also see this as 3*10^8 netwon seconds / kg.

Sometimes you see specific impulse in seconds as the Wikipedia article mentions, you have to multiply the figure in seconds by the acceleration of gravity in m/s^2, i.e by 9.8 m/s^2, to convert this to the correct units of velocity. Thus the specific impulse of a photon drive would be about 30 million seconds (354 days, about 1 year).
 

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