Calculating Relay Resistance for 12V Circuit

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SUMMARY

The discussion centers on calculating the resistance of a relay in a 12V circuit, where the relay activates at a current of 0.0048A. Given a series resistor of 800 Ohms, the calculation shows that the coil resistance is 1700 Ohms. The equation used is V = IR, leading to the conclusion that the total resistance in the circuit must equal 2500 Ohms to achieve the specified current. The participants confirm that the circuit is designed to deliver 0.0048A, validating the solution.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Basic knowledge of electrical circuits
  • Familiarity with series circuit configurations
  • Concept of relay operation and activation current
NEXT STEPS
  • Study advanced applications of Ohm's Law in circuit analysis
  • Learn about relay specifications and characteristics
  • Explore series and parallel circuit calculations
  • Investigate the impact of varying resistance on circuit performance
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Electrical engineering students, hobbyists designing circuits, and anyone involved in relay-based control systems will benefit from this discussion.

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Homework Statement



A relay switches on when the current through the coil reaches 0.0048A.

In a circuit, a battery of 12V is connected in series with this relay it switches on when another resistor of 800 Ohm is connected to it.

Calculate the resistance of the relay.

Homework Equations





The Attempt at a Solution



V= IR
12V = 0.0048A * (800 ohm + coil resistance)

12V / 0.0048A = 800 ohm + coil resistance

coil resistance = 2500 ohm - 800 ohm
=1700 ohm

However, I am not sure if I am on the right track...
 
Last edited:
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Is the circuit with the battery and the resistor supposed to deliver 0.0048A? If so, your solution is right.
 
ideasrule said:
Is the circuit with the battery and the resistor supposed to deliver 0.0048A? If so, your solution is right.

from the first line, "A relay switches on when the current through the coil reaches 0.0048A."

so can i conclude that the current passing through the coil has reached 0.0048A? which means that current in the circuit is 0.0048A

however, this question is worth 4 marks and it seems to easy for a usual 4 mark question...
 

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