Calculating Resistance for Cylindrical Conductors

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SUMMARY

The discussion focuses on calculating resistance for cylindrical conductors using the formula r = ρl/a, where r is resistance, ρ is resistivity, l is length, and a is the cross-sectional area. The user incorrectly calculated the area by using the outer radius instead of the average radius, leading to discrepancies in the final answer. The resistivity value used is 1.69e-8 Ω·m, and the dimensions provided include a length of 300 m and an outer radius of 6e-2 m with an additional thickness of 1.5e-3 m.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the formula for resistance in cylindrical conductors
  • Knowledge of resistivity values for different materials
  • Basic geometry for calculating areas of circles
NEXT STEPS
  • Review the derivation of the resistance formula for cylindrical conductors
  • Learn how to calculate the average radius for cylindrical geometries
  • Explore the impact of resistivity on electrical resistance in various materials
  • Investigate the effects of contact resistance in multi-layered conductors
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Students studying electrical engineering, physics enthusiasts, and professionals involved in materials science or electrical design who need to calculate resistance in cylindrical conductors.

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Homework Statement



can anybody help me with this question? my ans is different from the ans given... i need explanation on this ! here's my attempt by the way.
r=pl/a . r=resistance , p = resistivity l=length

r=(1.69e-8)(2pi )(6e-2 +1.5 e-3 )(300) / (pi )(1.5e-3)^2

what's wrong with my working? p/s e =1 x 10^x

Homework Equations





The Attempt at a Solution

 

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You ignored the perfect electrical contact between successive turns. You don't have a single long wire, you have a conducting cylinder.
(6e-2 +1.5 e-3 )
Minor detail: this is the outer radius, not the average radius.
 

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