Find R1: Resistance for Sinusoidal Current Network

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Discussion Overview

The discussion revolves around finding the resistance R1 in a sinusoidal current network, given specific values for R2 and X2, and a phase angle condition for the voltages U2 and U. The context includes homework-related problem-solving and mathematical reasoning involving complex numbers and phase angles.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states the problem involves finding R1 such that voltage U2 is in phase delay behind voltage U by an angle of -pi/6, with given values for R2 and X2.
  • Another participant suggests taking U as a reference and calculating R1 using the known angles of Z2 and U2.
  • A third participant reiterates that the phase angle of the expression involving R1 and the given values must equal -49.107°.
  • Further contributions include attempts to express the current I in terms of R1 and the known angles, while also expressing confusion about handling complex numbers in the calculations.
  • One participant arrives at a potential solution for R1, calculating it to be 35 ohms, but questions the validity of their earlier approach.

Areas of Agreement / Disagreement

Participants express various methods to approach the problem, but there is no consensus on the correctness of the initial approaches or the final value of R1. The discussion remains unresolved regarding the best method to compute R1 and the implications of complex number calculations.

Contextual Notes

Participants highlight challenges with complex numbers and the need for R1 to remain in the real domain. There are unresolved steps in the mathematical reasoning, particularly in how to compute the angle of a complex number.

Ivan Antunovic
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Homework Statement


In the network of sinusoidal current , R2 = 10 ohm , X2 = -30*sqrt(3) ohm. Find the resistance R1 so that voltage U2 is in phase delay behind voltage U for angle alpha = - pi / 6.

Homework Equations

The Attempt at a Solution


Z2 = sqrt(R^2 + X2^2) = 20*sqrt(7) ohms
fi2 = arctg(X2/R2) = -79. 107 degrees
fi = 30 + fi2 = -49.107 degrees

the rest is in the picture below.

The problem is that this last equation can only give complex solutions and R1 should be in real domain.
 

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See if this works:
Take U as reference(∠0°). You already have angle of Z2 w.r.t. U. You also have angle of U2 i.e I*Z2. Write an expression for current I which includes R1 and from the known angles, calculate R1.
 
Basically you want the phase angle of ##10 - j30\sqrt{3} + R1## to be -49.107°.
 
cnh1995 said:
See if this works:
Take U as reference(∠0°). You already have angle of Z2 w.r.t. U. You also have angle of U2 i.e I*Z2. Write an expression for current I which includes R1 and from the known angles, calculate R1.
You mean something like this?
image.png

uploading pictures
I put I at angle + 19 degrees so that U2 is at phase delay 30 degrees behind U.But still I am stuck with complex numbers.

gneill said:
Basically you want the phase angle of ##10 - j30\sqrt{3} + R1## to be -49.107°.
Yes if I put I at zero degrees Z = U / I = Z * exp(j*(-49)) but can't figure out how to use that information.
 
cnh1995 said:
See if this works:
Take U as reference(∠0°). You already have angle of Z2 w.r.t. U. You also have angle of U2 i.e I*Z2. Write an expression for current I which includes R1 and from the known angles, calculate R1.
This gives exactly what gneill said in #3.
Z2 is at an angle -79.107°. I*Z2 is at angle -30°. So, I must be at an angle 49.107°.
Since,
10-j30√3+R1=U∠0°/I∠49.107°,
angle of (10+R1)-(j30√3) is -49.107°.
How do you compute angle of a complex number a±ib?
 
Last edited:
arctg(-X2/(R1+R2)) = -49.107
-30sqrt(3) = -1.155R1 - 11.547
R1 = 35 ohms.

I am courious what was wrong with my approach?
 

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