Calculating S-F Bond Enthalpy from Standard Enthalpy of Formation Values

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Homework Statement


The values of standard enthalpy of formation of SF6(g), S(g), F(g) are -1100, 275, 80 kJ/mol resp. What is the average S-F bond enthalpy in SF6?


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The Attempt at a Solution


I read that the bond enthalpy is negative of enthalpy of formation from constituent atoms.
So average bond entalpy of S-F bond is 1100/6= 183.33kJ/mol. Is this correct?
 
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The heat of a reaction is = (ΔH of Products - ΔH of Reactants).

Consider the balanced equation SF6(g) --> S(g) + 6F(g).

Try calculating the enthalpy for the entire reaction based on the information given to you, and go from there.
 
What is the difference between enthalpy of entire reaction and enthalpy of formation of SF6? I think the enthalpy of formation is equal to enthalpy of reaction as SF6 is formed from its constituent atoms.