Calculating S & G for Phase Change of Water

[doomed]

phase change?

How do I calculate the values of change in entropy (S) and change in Gibbs free energy (G) for the conversion of n=1 mol of liquid water at 100 C and 1 bar pressure into vapor at the same temperatue and a pressure of 0.1 bar. Assume ideal behavior for the vapor. the molar enthalpy for vaporization of water at 100 C and 1 bar is 40.6 kJ/mol.

I know that delta S = delta H/T, but how the change in pressure play into this problem for delta S and delta G?

HELP me PLEASE!

 

[clive]

I'll give you some hints for the entropy:

You have 2 thermodynamic processes there:
1) vaporization
2) isothermal expansion form 1 bar to 0.1 bar.

Because the temperature is the same, the variation in entropy can easily be evaluated by
\Delta S=\frac{Q_1+Q_2}{T}
where Q1+Q2 represents the total transferred heat.

Now you have
Q_1=m\cdot \lambda_v
for the vaporization at 100 C
and
Q_2=\nu R T \ln \frac{V_2}{V_1}
for the isothermal expansion

and so on...(p_1 V_1=p_2 V_2 is the answer at your last question)

 

[quantumdude]

doomed,

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2.) Post homework questions in the Homework Help Forums, not the Physics Forum.