Calculating Sampling Rate of Sinc Signals - Nyquist Rate

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Discussion Overview

The discussion revolves around determining the appropriate sampling rate for sinc signals, particularly in the context of the Nyquist rate. Participants explore the implications of signal multiplication on bandwidth and sampling frequency, addressing both theoretical and practical aspects of signal processing.

Discussion Character

  • Technical explanation, Debate/contested, Homework-related

Main Points Raised

  • One participant seeks clarity on calculating the sampling rate for the signal sinc(200πt)*sinc2(400πt).
  • Another participant suggests that the sampling rate should be twice the highest frequency present, proposing a calculation of 2000π rad/s (or 1000 Hz) based on the combined bandwidths of the signals involved.
  • A different participant references a problem set with solutions that may provide additional context or guidance.
  • There is a mention of a specific case (10cos3(2π102t)) where the addition of frequencies did not yield the expected sampling frequency of 400 Hz, raising questions about the application of the Nyquist theorem in this scenario.
  • One participant questions the reliability of the provided answer in the problem set, suggesting it may pertain to a different problem and noting instances where sub-Nyquist sampling can be effective.

Areas of Agreement / Disagreement

Participants express differing views on the application of the Nyquist theorem and the validity of specific sampling frequency calculations. There is no consensus on the correct sampling rate for the discussed signals, and the conversation remains unresolved.

Contextual Notes

Participants highlight potential confusion arising from the interaction of signal multiplication and frequency addition, as well as the specific conditions under which sub-Nyquist sampling might be applicable.

Bijay
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I have tried calculating sampling rates for signals like sinc(200pi t). It was simple and I thought I understood until I cam across signals like sinc(200πt)*sinc2(400πt).

I need help with finding sampling rate of these kind of signals and get a clear concept on the topic.

Thanks in advance.
 
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You need to sample twice as fast as the highest frequency you expect to see. You also have multiplication of signals which makes their bandwidths add. So, in this case, I think you have to sample at ##2\left( 200\pi + 400\pi + 400\pi\right) = 2000\pi ##rad/s, or 1000 Hz.
 
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Here is a problem set with solutions that may help.

http://www.ee.columbia.edu/~mvp/e3801/hwk8_sols.pdf
 
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CopyOfA said:
You need to sample twice as fast as the highest frequency you expect to see. You also have multiplication of signals which makes their bandwidths add. So, in this case, I think you have to sample at ##2\left( 200\pi + 400\pi + 400\pi\right) = 2000\pi ##rad/s, or 1000 Hz.
But the adding of frequencies didnt worked for 10cos3 (2π102t). For this signal the sampling frequency is 400 hz
 
Bijay said:
But the adding of frequencies didnt worked for 10cos3 (2π102t). For this signal the sampling frequency is 400 hz
Who is more likely to be wrong - Nyquist or the guy who wrote the answer to the set problem? I guess that is what you are quoting, here. The answer in the book must be to another problem (quite possible). What answer did you get, btw?
There are examples when sub-nyquist sampling can work without impairment but this is not one of them.
 
https://www.physicsforums.com/threads/do-not-post-homework-or-coursework-questions-here-in-the-ee-forum.224442/
 

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