Calculating Shear Force for an Elastomeric Bearing Pad

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Discussion Overview

The discussion revolves around calculating the shear force for an elastomeric bearing pad subjected to a shear force, with specific dimensions and material properties provided. Participants explore the relationships between shear stress, shear strain, and the area of the bearing pad, while addressing unit conversions and arithmetic calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a formula for shear stress as t = Gy, where y is the shear strain calculated from displacement and thickness.
  • Another participant corrects the shear stress calculation, indicating it should be in MPa and provides the correct value based on the modulus of rigidity.
  • There is a discussion about the area of the pad and how to convert dimensions from millimeters to meters for consistent unit calculations.
  • Participants express confusion about the arithmetic involved in calculating shear force from shear stress and area, with differing interpretations of the results.
  • One participant expresses concern that their calculated shear force seems low compared to expectations based on previous examples.

Areas of Agreement / Disagreement

Participants generally agree on the formulas to use for shear stress and shear force, but there is disagreement and confusion regarding unit conversions and arithmetic calculations, leading to different interpretations of the final results.

Contextual Notes

Participants are working through the implications of unit conversions from millimeters to meters and ensuring consistent units throughout the calculations. There are unresolved arithmetic steps that lead to varying conclusions about the shear force value.

Who May Find This Useful

This discussion may be useful for students or professionals dealing with mechanical engineering concepts, particularly in the context of material mechanics and structural analysis involving elastomeric materials.

donniemateno
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Gents and Ladies

I have a question I have been given to work out shear force for.

The question is an elastomeric bearing pad is subjected to a shear force V

the top plate is found to have displaced by d = 12mm

dimensions of the top pad are a = 150mm by b = 200mm, the thickness (d) is 120mm. the modulus of rigidity G is 2 MPA

I have found a formula which is shear stress is t=Gy

y = d/h so 12 / 120 = 0.1

shear stress 2000 x 0.1 = 200 Kn

i fear i have done something wrong because i haven't used the dimensions of the plate. I have a formula which gives the average stress which is stress = v / ab but if i rearrange i get v = ab / stress
 
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any help at all ? please :)?
 
You calculated the shear strain correctly. The shear stress is equal to the shear strain times the shear modulus G. The shear stress should be in units of MPa. In your case the shear stress is 0.2 MPa. The shear force is equal to the shear stress times the area over which the stress is applied. What is the area of the pad? You do know that 1 Pa = 1 N/m2, and that 1 MPa = 1000000 Pa, correct?
 
so it should by 0.2 x 0.1? for shear stress? = 0.2 * area ( 150 * 200) = 30000 N so would it be 30Kn?
 
Please be more careful with your arithmetic.

Shear stress = 2 x 0.1 = 0.2 MPa

What is the area in square meters?

What is the stress times the area in consistent units?
 
Would my 150 and 200 mm become 1.5 and 2? making 3 square meters
 
No. Do you know the definition of a millimeter (mm)?
 
yes 1000mm to a meter 10mm to a cm

so my 150 mm and 200mm should be .15 * .2? this times by 0.2 would give me 0.006
 
Yes. Bu what are the units?
 
  • #10
Would this be 6 N? Seems very low. I thought the answer would be more like 6 Kn based on an example I have worked out gpa
 
  • #11
No. We already said that 1MPa = 1000000 N/m2. So if you apply the units correctly, you get 6000 N = 6 kN.
 
  • #12
Ive been asked to express answer is n not kn. Thank yu for your help :) sorry I am slow
 

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