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## Homework Statement

A cmedium carbon steel rod has a rectangular cross section and must cope with a tension of 29 430 Newtons . The thickness of the rod is 15 mm calculate the siz of the cross section?

## Homework Equations

A=P/Ok

**3. The Attempt at a Solution [/b**

O = UTS = 750 Mpa k = 0.25 P = 29 430 N t = 15 mm

A= P/Ok

29 430 / 200 = 187.50 mm^2

187.5 / t = 187.5 / 15 = 12.5 sqrt = 3.5355

Size of cross section = 12.5 mm x 3.5 mm

I believe I have the area correct but not sure if the sides are correct ?

O = UTS = 750 Mpa k = 0.25 P = 29 430 N t = 15 mm

A= P/Ok

29 430 / 200 = 187.50 mm^2

187.5 / t = 187.5 / 15 = 12.5 sqrt = 3.5355

Size of cross section = 12.5 mm x 3.5 mm

I believe I have the area correct but not sure if the sides are correct ?