Calculating something wrong with Poiseuille's Law

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SUMMARY

The discussion centers on the application of Poiseuille's Law to determine whether a person can breathe adequately through a tube measuring 100 cm in length and 2 cm in radius. The calculated volumetric air flow rate is 4.65 L/s, which suggests that breathing through the tube would not pose a problem. However, participants noted that this calculation may oversimplify real-world conditions, such as additional drag from the trachea and the necessity of drawing in fresh air. Ultimately, the conclusion is that while the theoretical flow rate is high, practical considerations must be taken into account for accurate assessments.

PREREQUISITES
  • Understanding of Poiseuille's Law for volumetric flow rate
  • Basic knowledge of respiratory physiology, including normal breathing rates and volumes
  • Familiarity with units of pressure (mmHg and Pa) and viscosity (Pa s)
  • Concept of air flow dynamics in tubes and the impact of drag
NEXT STEPS
  • Study the implications of Poiseuille's Law in biological systems
  • Research the effects of airway resistance on respiratory efficiency
  • Learn about the anatomy of the respiratory system, focusing on the trachea and its role in airflow
  • Explore real-world applications of fluid dynamics in medical devices, such as ventilators
USEFUL FOR

Students studying respiratory physiology, healthcare professionals involved in respiratory therapy, and anyone interested in the principles of fluid dynamics as applied to human biology.

dvora
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Homework Statement



At resting, can you breath sufficient air through a tube of 100 cm length and 2 cm radius?

normal resting respiration rate: 10 - 20 breaths per minute (3 - 6 seconds per breath)

normal resting respiration volume: 0.5 L

normal pressure difference in respiration = 1 mmHg = approximately 133.322 Pa

viscosity of air is apparently 0.0018 Pa s

Homework Equations



Poiseuille's Law for volumetric air flow: Fv = ((P1-P2)pi(r^4)) / 8 eta L

The Attempt at a Solution



Fv = (133.322 Pa * pi * .02 m^4) / (8 * .0018 Pa s * 1 m) = 0.00465 m^3/s = 4650 cm^3/s = 4.65 L/s inhalation

So the conclusion would be that you'd have no problem breathing through the tube.

This seems like an awfully fast rate of inhalation, which makes me wonder if I am doing something wrong. I have never taken a physics class, I am taking a class in which physics is not supposed to be a requirement and we have never discussed or read about air flow in class, but we have been given this problem as a homework assignment. Which is all a way of saying that I know nothing about physics and would greatly appreciate it if somebody could show me where I went wrong and why. Do I have a problem with my units or something?

The other possibility is that this just looks like a really fast rate because it's oversimplified and doesn't include the rate of air flow through the trachea.

Thanks!
 
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I'm not sure what you are expected to take into account, but it seems to me that in the real world there are two significant aspects your calculation ovelooks:
1. The drag in the tube is in addition to the drag that is already present in drawing the air through the nostrils etc.
2. To breathe successfully through the tube, enough fresh air must be drawn in each time. If the expelled air goes through the tube also then the total tube volume may be too great.
 
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Thank you! I had just looked up the tracheal air flow when you replied and it's slower than air flow through the tube, so I can base my calculations on the rate of tracheal air flow instead. Maximal inspiration/expiration volume is greater than resting inspiration volume + dead space in the tube, so I think the person should be able to get enough fresh air even breathing out through the tube.
 
We weren't told what to take into account; we were just told to decide whether or not people can breathe with a 100 cm length, 2 cm radius tube. We've also never discussed solving problems like this, so I'm just guessing about what to take into account.
 
dvora said:
We weren't told what to take into account; we were just told to decide whether or not people can breathe with a 100 cm length, 2 cm radius tube. We've also never discussed solving problems like this, so I'm just guessing about what to take into account.
Ok, sounds good.
 
dvora said:
Thank you! I had just looked up the tracheal air flow when you replied and it's slower than air flow through the tube, so I can base my calculations on the rate of tracheal air flow instead. Maximal inspiration/expiration volume is greater than resting inspiration volume + dead space in the tube, so I think the person should be able to get enough fresh air even breathing out through the tube.

That, of course, is assuming that I've correctly calculated the air flow through the breathing tube.
 
dvora said:
That, of course, is assuming that I've correctly calculated the air flow through the breathing tube.
I could not see an error, and it does seem reasonable. That is quite a large radius, so I'm not surprised it yields a greater flow rate that the respiratory tract, particularly if the normal pressure diffence you quote is for breathing through the nose.
 
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Thank you for all of your help!:smile:
 

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