Calculating Speed of Golf Ball After Contact

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Homework Help Overview

The discussion revolves around calculating the speed of a golf ball after being struck, given its mass, the average force applied, and the time interval of contact. The problem is situated within the context of classical mechanics, specifically involving concepts of force and motion.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the impulse-momentum theorem, with one posting a calculation for speed based on the formula v=Ft/m. Questions arise regarding the correctness of the answer and the reasoning behind it.

Discussion Status

The discussion is ongoing, with some participants expressing confidence in the calculations while others seek further clarification or validation of the results. There is an exchange of thoughts on the complexity of the problem, indicating a mix of understanding and uncertainty.

Contextual Notes

Participants are operating under the assumption of neglecting air resistance and considering a level course, which may influence the interpretation of the problem. There is also a note about marking the thread as 'solved' once clarity is achieved.

jinman
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Homework Statement



i hit a golf ball of mass 0.045kg with an avg. Force of 2.5x10^3 N over a short time interval of 1.0 x 10^-3 s at an angle of 30 degrees with respect to the horizontal. neglect air resistance and assume a level course.

What is the speed of the ball immediately after contact?


Homework Equations



Ft=mv


The Attempt at a Solution




v=Ft/m

2500x.001/.045

v=55.6m/s?

If that is the wrong answer why? If that is right can someone further explain it to me?
 
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jinman said:

Homework Statement



i hit a golf ball of mass 0.045kg with an avg. Force of 2.5x10^3 N over a short time interval of 1.0 x 10^-3 s at an angle of 30 degrees with respect to the horizontal. neglect air resistance and assume a level course.

What is the speed of the ball immediately after contact?

Homework Equations



Ft=mv

The Attempt at a Solution

v=Ft/m

2500x.001/.045

v=55.6m/s?

If that is the wrong answer why? If that is right can someone further explain it to me?
It looks fine to me. What do you need explaining?
 
why would you think it's wrong?
 
Hrmmm. I thought it would be Harder. Thank you!
 
jinman said:
Hrmmm. I thought it would be Harder. Thank you!
No problem :smile:

Don't forget to mark the thread as 'solved' when you're done.
 

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