Calculating Speed of Simple Pendulum at 25° Angle

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SUMMARY

The speed of a simple pendulum with a length of 2.0 m, released from an angle of 25° from the vertical, is calculated using conservation of energy principles. The correct speed at the lowest point of the swing is 1.9 m/s, derived from equating kinetic energy at the lowest point to potential energy at the highest point. The vertical height change is determined by the formula 2 - 2.cos(25°). The confusion arose from an incorrect calculation of the height change and its impact on the speed.

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Homework Statement



A simple pendulum, 2.0 m in length, is released from rest when the support string is
at an angle of 25° from the vertical. What is the speed of the suspended mass at the
bottom of the swing?

Homework Equations



R2= X2 + Y2

The Attempt at a Solution



I know the answer is 1.9ms-1

but i keep getting 1.8126ms-1

which is 2.cos(25)
what am i doing wrong?
 
Physics news on Phys.org
If you are going to use conservation of energy, for example, then you equate the k.e. at the lowest point to the p.e. at the highest.
The mass has risen a vertical height 2 - 2.cos25. when moved to its starting point.
 

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