Calculating Stopping Potential in Photoelectric Effect Experiment

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SUMMARY

The discussion centers on calculating the stopping potential in a photoelectric effect experiment, specifically when ultraviolet light of wavelength 380 nm yields a stopping potential of 2.70 eV. Participants clarify that while stopping potential is technically measured in volts (V), it is often expressed in electronvolts (eV) due to the context of electron energy. The consensus is to provide the answer in volts while acknowledging the common misuse of units in the question. The numerical results remain consistent regardless of the unit used.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with the concept of stopping potential
  • Knowledge of energy units, specifically electronvolts (eV)
  • Basic grasp of wavelength and its relation to energy (E = hc/λ)
NEXT STEPS
  • Review the principles of the photoelectric effect and its equations
  • Study the conversion between electronvolts (eV) and volts (V)
  • Learn about the implications of wavelength on stopping potential in photoelectric experiments
  • Explore common misconceptions in units of measurement in physics
USEFUL FOR

Students in physics, educators teaching the photoelectric effect, and anyone interested in understanding the nuances of energy and potential measurements in experiments.

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Homework Statement


In a photoelectric experiment, a stopping potential of 2.70 eV is measured when ultraviolet light of wavelength 380 nm is incident on the metal. If blue light of wavelength 440 nm is used, what is the new stopping potential in eV?

Homework Equations

The Attempt at a Solution


I think i understand how to do this problem (qV = hc/λ - work function) but am very confused as they have given and ask for the stopping potential in eV. I thought that eV was a unit of energy and that stopping potential (as it is a voltage) is given by the units V. How can the units of a potential be eV?
 
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You're right. The stopping potential should really be measured in V, not eV. But since it is electrons you are stopping, people sometimes get sloppy and refer to electron energy (in eV) rather than the potential (in V).
 
So i should give the answer for the energy and not the potential?
 
The numerical results should be the same. I would five the answer in V, and explain that the question is really incorrect, since potentials are measured in V.
 
ok thank you very much!
 

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