Calculating T2(x) at -1 with Error Less than 1/80 for f(x)=1/1-2x

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SUMMARY

The discussion focuses on calculating T2(x) for the function f(x) = 1/(1-2x) at the point x = -1, within the interval [-1.5, -1], ensuring the error remains below 1/80. The third derivative of the function is determined as f'''(x) = 48/(1-2x)^4, with the specific value f'''(-1.5) calculated to be 3/16. To achieve the desired error threshold, participants suggest using the (n+1)th derivative to establish an upper bound on the error by evaluating the maximum absolute value of the derivative within the specified interval.

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vickymath
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i really need help with this prob f(x)=1/1-2x i have to calculate T2(x) at -1 on the interval -1.5,-1 with an error less than 1/80.
I got f"'=48/(1-2x)^4 and f"'(-1.5)=3/16 and i can't get the error at 1/80 . Thank you
 
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There are several methods to give an upper bound on the error. The one I would use requires the (n+1)th derivative at some point in the interval - take the point where the absolute value of the derivative has the largest value for an upper bound.

Does this help to fill the gaps in your answer?
 
yep, thank you
 

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