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You got it. Sleep well.gracy said:So T-150=30 multiplied by6
T=330 N
The discussion focuses on calculating the tension in a string connected to a block on a flat car accelerating at 3 m/s². The block has a mass of 30 kg and a coefficient of friction of 0.50. The key equations used include Newton's second law (F = ma) and the frictional force formula (Friction = μN). The participants clarify that the block's acceleration is not the same as the car's due to the frictional force acting in the opposite direction, leading to a tension calculation of T = 150 N + (30 kg * 3 m/s²).
PREREQUISITESStudents of physics, mechanical engineers, and anyone interested in dynamics and force analysis in systems involving friction and pulleys.
You got it. Sleep well.gracy said:So T-150=30 multiplied by6
T=330 N
Really fast service ,I got this after 88 you in 10 th post.dean barry said:if the acceleration of the block = 2 * truck acceleration, then the force required in the string = m * a
then add the friction force