Calculating the Equation of a Transverse Wave

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SUMMARY

The equation of a transverse wave can be expressed as y(x,t) = A sin(kx ± ωt + φ). For a wave with a frequency of 75.0 Hz and a wavelength of 0.190 m, the wave number (k) is calculated as 33.06, and the angular frequency (ω) is 472.4 rad/s. The amplitude (A) is given as 0.7 m, and the initial transverse velocity is +350 m/s. The phase constant (φ) needs to be determined based on the initial conditions provided.

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Write the equation of a transverse wave that has a frequency of 75.0 hz, wavelength of .190m,an initial height of .7m and initial transverse velocity of +350m/s traveling in the negative direction.Also sketch at t=0




y(x,t)=Asin(kx+/-ωt+φ)

K=33.06
ω=472.4rad/s
φ=
A=
x=
y=
that's all i remember how to find

y(x,t)=Asin(33.06x+472.4t+φ)
 
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What parameter in the equation refers to the Amplitude of the wave?
 
A is the amplitude
x is the space coordinate
t is the time coordinate
k is the wavenumber
ω is the angular frequency
φ is the phase constant.
 
Any one?
 
You will also need the equation for the transverse velocity of the wave as function of t and x. Set t=0 and plug the initial height and transverse velocity given in the problem.
 

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