Calculating the Force Opposing Gravity in Orbital Simulations

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SUMMARY

This discussion focuses on calculating the force opposing gravity in orbital simulations, specifically between the Earth and the Sun. The gravitational force exerted by the Sun on the Earth can be equated to the centripetal force required to maintain Earth's orbital velocity of approximately 1.47 kilometers per second. The formula v²/r is suggested for calculating the necessary centripetal force, where v is the orbital velocity and r is the radius of the orbit. The two forces are in equilibrium, indicating they are roughly equal in magnitude.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with centripetal force concepts
  • Basic knowledge of orbital mechanics
  • Proficiency in programming for simulations
NEXT STEPS
  • Research Newton's Law of Universal Gravitation and its applications
  • Learn about centripetal force calculations in orbital mechanics
  • Explore programming libraries for simulating gravitational interactions
  • Investigate the effects of varying orbital velocities on gravitational forces
USEFUL FOR

Astrophysicists, software developers working on simulation programs, and students studying orbital mechanics will benefit from this discussion.

bkelly
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I am writing a program to do some orbital simulations. For ease of conversation, let's start with the sun and the earth. If the Earth were standing still, the sun would pull it in quite rapidly. As the Earth is moving at about 1.47 kilometers per second, that movement creates a force opposing the suns gravity. How do I calculate that force?
 
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v^2/r ?
 
Quick and dirty way: look up the Sun's gravitational force on the Earth (the two forces are in equilibrium, so they are roughly the same amount of "force").
 

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