Calculating the Fringe Width without the value of its Wavelength

  • Thread starter AJ786
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Homework Statement



Young's fringes, produced by monochromatic laser light passing through slits 0.60mm apart, are viewed on a screen. The distance accrose 20 fringe spacings on the screen is 58mm. When the screen is moved 0.80m away from the slits, the distance across 20 fringe spacings becomes 74mm.

Homework Equations



Y = D(lamda) / d

Y = Fringe Width
D = Distance from slits to screen
d = spacing between slits
(lamda) = Wavelength

The Attempt at a Solution

 
Last edited:

Answers and Replies

  • #2
rl.bhat
Homework Helper
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In the experiment wavelength and slit width is constant. There fore
Y1/Y2 = D1/D2.
Y1 and Y2 is given. D1 is not given. But D2 = D1 + 0.80 m.
Substitute these values in the above relation and find D1.
Then using the relevant equation, you can find the wavelength.
 
  • #3
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Are Y1 and Y2 0.60mm and 74mm as Y is what I need to calculate so surely this would not be given to me within the question ?
 
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