- #1
Ravi Mandavi
- 36
- 0
how, limit h->0 {(e^h-1)/h}= 1?
Although this is not home work but i stuck on it
Although this is not home work but i stuck on it
The limit of {(e^h-1)/h} as h approaches 0 is equal to 1. This can be proven using L'Hôpital's rule or by taking the limit of the function as h approaches 0.
Calculating the limit of {(e^h-1)/h} as h approaches 0 is important in many areas of mathematics and science, particularly in calculus and differential equations. It allows us to understand the behavior of a function as it approaches a specific point.
Yes, the limit of {(e^h-1)/h} as h approaches 0 can also be solved using algebraic manipulation and the properties of limits. However, using calculus is often the most efficient and accurate method.
The number e is a mathematical constant that is approximately equal to 2.71828. It is a fundamental constant in calculus and is often used in the study of exponential growth and decay.
Yes, there are many real-world applications of calculating this limit, such as in physics, engineering, and economics. It is used to model and predict various phenomena, such as population growth, radioactive decay, and interest rates.