Calculating the Mass Flow Rate for Point C

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Homework Help Overview

The discussion revolves around calculating the mass flow rate at a specific point in a fluid dynamics problem, particularly focusing on point C. The problem involves understanding the relationship between velocity, area, and mass flow rate in the context of fluid flow through a pipe with varying diameters.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of mass flow rate using given velocity and area, while questioning the relevance of additional information provided in the problem. There is a focus on the implications of pipe diameter changes on flow speed and mass flow rate at different points.

Discussion Status

Some participants have confirmed the calculations presented, while others are exploring the potential for misleading information in the problem statement. There is an ongoing examination of how the details might influence the understanding of mass flow at different points in the system.

Contextual Notes

Participants note that the problem may contain extraneous information, prompting discussions about how to discern essential details from those that are not useful. The implications of the pipe's width at different points are also under consideration.

jimbo71
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Homework Statement


see attachment


Homework Equations


Av=dV/dt
mass flow rate =roe*dV/dt



The Attempt at a Solution


the velocity at point c is 50m/s and the area of the opening is 0.04m^2. (50m/s)(0.04m^2)(1000kg/m^3)=2000Kg/s
 

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Do you think these questions sometimes give you extra information in order for you to show that you know how to sort out the essential from the not useful?
At point B the pipe is wider than at C.
At B will the water be flowing faster, slower, or the same speed as a point C ?
Obviously the same amount of water must pass point B and point C.
So what can we say about the mass flow at B?
 
jimbo71 said:

Homework Statement


see attachment


Homework Equations


Av=dV/dt
mass flow rate =roe*dV/dt



The Attempt at a Solution


the velocity at point c is 50m/s and the area of the opening is 0.04m^2. (50m/s)(0.04m^2)(1000kg/m^3)=2000Kg/s

Looks correct to me.

CS
 
Stewart,
Yes he's right, but the question gives a lot of unnecessary detail and I was trying to see if he was misled by it.
 
I was a little mislead by the simplicity of the problem. Since the 6th grade, I've known some problems give more information than needed.
 
Carid said:
Stewart,
Yes he's right, but the question gives a lot of unnecessary detail and I was trying to see if he was misled by it.

Typically when students give the correct answer it implies that they were not mislead by it! :wink:

CS
 

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