Calculating the Period of Deimos: Phobos vs Deimos

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To calculate the orbital period of Deimos, the user correctly applies Kepler's Third Law, which states that the square of the period ratio equals the cube of the radius ratio. With Phobos' average radius of 9380 km and period of 0.319 Earth days, and Deimos' radius of 23500 km, the user can set up the equation accordingly. The choice of which satellite to label as A or B is flexible as long as the ratios are consistently applied. This method will yield the correct period for Deimos. The discussion confirms the validity of the approach taken.
StaticShock
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Here's the problem:

Phobos and Deimos 2 satalites of mars, ahve orbits with average radii of 9380km and 23500km respectivly.

The period of Phobos is .319 Earth days. Whats is the period of Demos?

I ahve it set up like this:

Rp=9380
RD=23500
Pp=.319
Pd=?

and i know (Ta\Tb)sq'ed =(Ra\Rb)cubed. Am I right in doing this? How do I choose who is A and who is B?
 
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Rp=9380
RD=23500
Pp=.319
Pd=?
and i know (Ta\Tb)sq'ed =(Ra\Rb)cubed. Am I right in doing this? How do I choose who is A and who is B?

Your approach is right. Choose them however you like. As long as you're consistent, it will be fine.
 
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