What Is the Radius of the n = 6 Bohr Orbit in O7+?

  • Thread starter Thread starter rayfieca
  • Start date Start date
  • Tags Tags
    Radius
Click For Summary
To calculate the radius of the n = 6 Bohr orbit in O7+, the relevant formula must account for the nuclear charge, which is Z=8 for oxygen. The standard equation r(n) = (n^2) * a(b) applies to hydrogen-like atoms but needs modification for different atomic numbers. The correct radius for the n = 6 orbit in O7+ is 238 pm, which requires using the adjusted formula that incorporates the atomic number. Users are encouraged to consult resources on "hydrogen-like" ions for a clearer understanding. Accurate calculations depend on recognizing the influence of nuclear charge on the orbit radius.
rayfieca
Messages
5
Reaction score
0

Homework Statement


Calculate the radius of the n = 6 Bohr orbit in O7+(oxygen with 7 of its 8 electrons removed).
A) 190 pm B) 167 pm C) 238 pm D) 214 pm


Homework Equations



I believe that the relevant equation is
r(sub n)=(n^2)*a(sub b) where a(sub b)= Bohr's radius= 5.29*10^-11 m

The Attempt at a Solution


I calculated it for what I believed to be n=6, but I got an incorrect answer. The correct answer is (C) 238 pm, but I do not understand why.


Any help is greatly appreciated!
 
Physics news on Phys.org
Your formula is not quite complete. You need to take into account the charge in the nucleus (so the number of protons).
 
Welcome to PF :smile:

Your equation is for hydrogen, with a charge of +1 on the nucleus.
Since oxygen has a charge of Z=8 for the nucleus, that equation should be different, containing Z somehow.

Does your textbook discuss "hydrogen-like" or "hydrogenic" ions?

EDIT: ah, I should know better than to wait a 1/2 hour and then respond without refreshing the page. :redface:
 
Unfortunately,
I cannot find an equation that takes into account (Z). Anyone have the equation handy?
Thanks for all your help!
 
Thank you very much!
 

Thread 'Magnitude of buoyant force in fluids of different densities'

The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
View full post »

Similar threads

Finding the radius of the satellite's circular orbit
  • · Replies 3 ·
Replies
3
Views
2K
Find at what rate the orbit radius will grow
  • · Replies 30 ·
2
Replies
30
Views
2K
What is the Orbit of Hydrogen Atom for an Electron at 734 km/s?
  • · Replies 3 ·
Replies
3
Views
2K
Electron acceleration in its lowest orbit
  • · Replies 3 ·
Replies
3
Views
1K
When do I include the Earth's radius in questions involving satellites?
  • · Replies 5 ·
Replies
5
Views
2K
What is the orbital radius of a muon captured in the n=1 ground state of Carbon?
  • · Replies 13 ·
Replies
13
Views
3K
Bohr-Sommerfeld model question "Old" Quantum Theory
  • · Replies 8 ·
Replies
8
Views
3K
Solving Bohr Atom Problem (Qs a-e)
  • · Replies 13 ·
Replies
13
Views
2K
How do you modify the Bohr model equation for Li++?
  • · Replies 3 ·
Replies
3
Views
2K
What is the Radius of Bohr Atom Orbitals?
  • · Replies 1 ·
Replies
1
Views
3K