Calculating the Speed of a Charge at Point A in an Electric Field

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SUMMARY

The discussion focuses on calculating the speed of a charge at point A in an electric field, specifically for a scenario involving two point charges: q1 = +2.40 nC and q2 = -6.50 nC, separated by 0.100 m. The user successfully calculated the electric potentials at points A and B, yielding VA = -737 V and VB = -704 V, and determined the work done on a 2.50 nC charge traveling from point B to A as WB->A = +8.2 x 10-8 J. However, the user encountered difficulty in calculating the speed of the charge at point A due to the absence of mass in the problem statement, which is essential for applying the kinetic energy equation KE = 1/2 mv2.

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For this question, I have solved letters a, b and c. I'm stuck at letter d.

Homework Statement


Two point charges ql = +2.40 nC and q2 = -6.50 nC are 0.100 m apart. Point A is midway between them; point B is 0.050 m from ql and 0.060 m from q2 (Fig). Take the electric potential to be zero at infinity. Find
(a) The potential at point A;
(b) The potential at point B;
(c) The work done by the electric field on a charge of 2.50 nC that travels from point B to point A.
(d) The speed of the 2.50 nC when it reaches point A, if it starts from rest at point B

Homework Equations



KE = 1/2 m v2 ?

The Attempt at a Solution


I have solved a, b and c

a) VA = -737 V
b) VB = -704 V
c) WB->A = +8.2 x 10-8 J

Now I'm stuck at letter D, how do i find the speed? I assume that I might need the equation of KE = 1/2 m v2.. But I don't know how to do it.

What I did was to put +8.2 x 10-8 J as my KE. However, I do not have a mass, so how do I do this?
 
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Your method is fine. You can't solve this problem without having the mass of the charge.
 
Oh you mean that the problem is missing the mass? If that's so then I cannot solve this.
 

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