Calculating the Taylor Series for cos(x) in Powers of x-pi | Homework Help

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To find the Taylor series representation of f(x) = cos(x) in powers of x - π, the series should be expanded around x = π instead of the usual x = 0. This means that the "a" value in the Taylor series formula is π. The general term of the Taylor series can be expressed as f^(n)(π) * ((x - π)^n) / n!. This approach clarifies the process of calculating the series by substituting π for "a" in the formula. Understanding this concept is crucial for accurately representing the function in the desired form.
TheRedDevil18
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Homework Statement



Find the taylor series representation for the following function
f(x) = cos(x) in powers of x-pi

Homework Equations


The Attempt at a Solution


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I don't know what they mean by "in powers of x-pi", that's the part I'm confused with. Can somebody please explain that part for me, thanks
 
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That just means you should expand around x=\pi rather than the usual x=0.
 
Shyan said:
That just means you should expand around x=\pi rather than the usual x=0.

Does that mean the "a" value is pi ?
 
TheRedDevil18 said:
Does that mean the "a" value is pi ?
If you write f(a+\delta)=\sum_{n=0}^\infty \frac{f^{(n)}(a)}{n!} \delta^n, then yes!
 
I use this formula

f^(n)(a)*((x-a)^n)/n!

And sub in pi for a, thanks
 
TheRedDevil18 said:
I use this formula

f^(n)(a)*((x-a)^n)/n!

And sub in pi for a, thanks
Yes, this is what the general term in your Taylor series will look like. Note that a Maclaurin series is a special case of a Taylor series, where a = 0.
 
Ok , thanks
 

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