Calculating the torque required to rotate a ski on snow

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SUMMARY

The discussion focuses on calculating the torque required to rotate the front skis of a toboggan for the Great Northern Concrete Toboggan Race. The user has established the normal force and frictional force on each ski but seeks further information to accurately compute the torque needed to overcome friction. Key factors include the ski's surface area and moment of inertia, which directly influence the torque calculation. The pivot axis is centered on the 24-inch skis, which is critical for determining the required force for pivoting.

PREREQUISITES
  • Understanding of torque calculations in mechanical engineering
  • Knowledge of frictional forces and their impact on movement
  • Familiarity with moment of inertia concepts
  • Basic principles of pivot mechanics
NEXT STEPS
  • Research the equations for calculating torque in rotational systems
  • Study the effects of surface area on frictional force
  • Learn about moment of inertia for different shapes and materials
  • Explore pivot mechanics and their applications in engineering design
USEFUL FOR

Engineering students, mechanical engineers, and anyone involved in designing or analyzing the mechanics of toboggans or similar vehicles.

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Hello friends,

I'm currently working on an engineering competition project known as the Great Northern Concrete Toboggan Race, and I'm stuck on some preliminary calculations. I'm trying to calculate the amount of torque that will be required to rotate the front skis in order to turn the toboggan. I have determined a normal force on each ski, and therefore a frictional force, but I believe I am missing information required to calculate the true torque needed to overcome friction. Common sense tells me a larger ski will require more torque to overcome friction, so how do I factor in surface area? Is moment of inertia also relevant?

Any insight would be much appreciated, thank you.
 
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What do you mean by Concrete Toboggan Race ?
 
Nidum said:
What do you mean by Concrete Toboggan Race ?

It's a competition for engineering students. It's essentially a steel roll cage with a concrete running surface. In my case, there's two fixed skis in the back and two skis in the front that will be able to pivot. I'm trying to figure out how much force it will take to achieve that pivoting
 
Where's the "pivot center" located? Leading? Trailing?
 
The pivot axis is centered on each ski, which are 24 inches in length
 

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