Calculating Total Energy of Positron and Electron in Quantum Physics Problem

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The discussion centers on calculating the total energy of a positron and an electron in a quantum physics problem. The rest energy of the electron is 0.511 MeV, while the positron has a kinetic energy of 0.158 MeV. To find the total energy, one must add the rest energy of the electron to the sum of the rest and kinetic energies of the positron, resulting in a total of 1.180 MeV. Participants clarify that the total energy of the positron includes both its rest and kinetic energies, leading to the correct calculation. The thread concludes with appreciation for the assistance provided.
aurao2003
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Homework Statement



Hi
I am new to this forum and offering quantum physics at A level. Can anybody help with the following problem:

The rest energy of an electron is 0.511MeV. A positron created in a cloud chamber has 0.158MeV of kinetic energy. It collides with an electron at rest, creating two photons of equal energies as a result of annihilation.

1. calculate the total energy of the positron and the electron.
2. show that the energy of each photon is .590MeV.

Thanks
Ben

Homework Equations





The Attempt at a Solution

 
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Hint: What is the total energy of the positron?
 
The total energy should be 0.511 x 2. Since the electrons rest energy is 0.511 any particle colliding with it will have the same energy.
 
aurao2003 said:
The total energy should be 0.511 x 2. Since the electrons rest energy is 0.511 any particle colliding with it will have the same energy.
Huh? That does not make any sense to me at all. Why should the energy of any other particle be affected by the rest energy of the electron??
Total energy of the system is simply just the sum of the total energies of the electron and the positron. We know that the total energy of the electron is simply its rest energy, 0.511 MeV. So now all we need to do is get the energy of the positron. What is it?
 
The energy of the positron is 0.158MeV. Therefore the total energy of the system is 0.158+0.511=0.669 MeV. However the answer is 1.180 MeV.
 
aurao2003 said:
The energy of the positron is 0.158MeV. Therefore the total energy of the system is 0.158+0.511=0.669 MeV. However the answer is 1.180 MeV.
0.158 MeV is the kinetic energy of the positron. The total energy of the positron is the sum of its kinetic and rest energies.
 
Fightfish said:
0.158 MeV is the kinetic energy of the positron. The total energy of the positron is the sum of its kinetic and rest energies.


Thats true. But I wonder how they obtained 1.180 MeV. Please explain. Thanks.
 
The total energy of system = energy of electron + energy of positron
= 0.511 MeV + (0.511 MeV + 0.158 MeV)
= 1.180 MeV
 
Fightfish said:
The total energy of system = energy of electron + energy of positron
= 0.511 MeV + (0.511 MeV + 0.158 MeV)
= 1.180 MeV

Thanks a lot. Have a nice day.

Regards
Ben
 

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