1. The problem statement, all variables and given/known data a. What is the net resistance of the circuit connected to the battery in the figure above? Each resistor has the same resistance R. Give your answer as a number times R b. What is the net resistance if the diagonal resistor between nodes A and B is replaced by a resistance of 1.9 R? 2. Relevant equations Combining Resistors Resistors in Series: R(eq)=R1+R2+R3..... Resistors in Parallel: R(eq)=1/R1+1/R2+1/R3...... 3. The attempt at a solution I feel like I did everything right but my answer or 13R/7 is wrong. I labeled the Resistors: starting from the left side of square, R1, then the top R2, diagonal resistor R3, bottom of square R4 and right side of square R5 and the bottom resistor R6 (maybe I didn't need to go through all that to label them but I feel like it would be easier to understand my attempt of solving this). R1 and R2 are in series so adding them, I get 2R Substituting R1 and R2 with a single 2R resistor, that one resistor would be in parallel to R3 so I get 3/2R Then substituting one resistor for those, that one would be in series to R5 so I got 5R/3 then substituting one resistor for those, that one would be in parallel to R4 (bottom of square) so adding those, I got 6R/7 and adding the last resistor (in series) I got a total of 13R/7 Not sure where I went wrong, please help.