- #1

qubert

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Question is:

plane flies at a speed of 100m/s at a height of 18m above water

plot the trajectory from release to first impact point, in intervals of 0.2m

managed this and have plotted the trajectory, with relevant velocities and resultant but the next part asks:

"At each bounce the vertical and horizontal velocity is reduced by a factor of 0.696, if the resultant speed has to be between 5 and 6m/s determine the number of bounces and horizontal distance the bomb requires without bouncing over."

how would one rearrange the equations finding the first trajectory without knowing the height the second bounce starts from?

i thought maybe by using a quadratic and pythagoras:

(100x0.696B)^2+(18.78x0.696B)^2=5.5^2 where b is the number of bounces, 100 and 18.78 are the horizontal and vertical velocities on the first drop

is this anywhere near correct?

thanks

plane flies at a speed of 100m/s at a height of 18m above water

plot the trajectory from release to first impact point, in intervals of 0.2m

managed this and have plotted the trajectory, with relevant velocities and resultant but the next part asks:

"At each bounce the vertical and horizontal velocity is reduced by a factor of 0.696, if the resultant speed has to be between 5 and 6m/s determine the number of bounces and horizontal distance the bomb requires without bouncing over."

how would one rearrange the equations finding the first trajectory without knowing the height the second bounce starts from?

i thought maybe by using a quadratic and pythagoras:

(100x0.696B)^2+(18.78x0.696B)^2=5.5^2 where b is the number of bounces, 100 and 18.78 are the horizontal and vertical velocities on the first drop

is this anywhere near correct?

thanks

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