Calculating Transformer Input Voltage

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The discussion focuses on calculating the primary current and input voltage of a transformer using given parameters such as transformation ratio, resistances, and reactances. Participants explore the equivalent circuit calculations, including the use of complex numbers for impedance. There is a debate over the efficiency of the provided solution, particularly regarding the absence of a specific value for Xm in the original problem statement. Some contributors suggest that the solution could be simplified and express concerns about the complexity relative to the marks assigned. The conversation emphasizes the need for clarity in problem statements and the potential for alternative methods in solving transformer-related calculations.
MechEngJordan
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Homework Statement



Calculate the primary current, and hence the voltage at the transformer input winding, V1.

Transformation ratio, a = N1/N2 = 0.1
R1 = 0.12 Ω; R2 = 12 Ω
X1 = 0.4 Ω ; X2 = 40 Ω
RC = 560 Ω
V2 = 2300 V
RL = 1 kΩ
'Xm = 800 Ω'

Homework Equations



R1eq = R1 + a2R2
X1eq = j(X1 + a2X2)
V2' = aV2

Current divider equation.

The Attempt at a Solution


[/B]
Approximate equivalent circuit:

Screenshot (206).png


R1eq = 0.12 + (0.1)2(12)
R1eq = 0.24 ΩX1eq = j(0.4 + (0.1)2(40))
X1eq =j0.8 Ω

V2' = 0.1(2300)
V2' = 230 V

a2ZL = (0.1)2(1000)
a2ZL = 10 Ω

Ip = V2'/a2ZL
Ip = 23 AFrom here is where I believed that there is likely a more efficient way to solve the problem -- particularly because the value of Xm was not actually given in the paper, but told to us during the tutorial, more-or-less made up on the spot.

Here is the outline of the given solution:

Ip= I1*Z2/(Z1+Z2)

⇒I1 = Ip*(Z1+Z2)/Z2

⇒I1 = 23*(Rc // Xm + X1eq + R1eq + a2ZL)/ (Rc // Xm)I0 = I1 - Ip

∴ V1 = I0(Rc // Xm)

I'd be thankful for any input.
 
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MechEngJordan said:
From here is where I believed that there is likely a more efficient way to solve the problem

It seems that in the given solution another equivalent is used (T-equivalent) than the one in #1. It's hard to explain what happens in that other equivalent because I cannot see what is meant by Z1 and Z2.

Don't you like to calculate with complex numbers? I don't know if you find complex calculations "more efficient", but they will be more structured. Example:

Z0 = (Rc || jXm) = (560 || j800) = (375.8 + j263). That's it.

In the same way you calculate other impedances, that can be used in Kirchhoffs laws, etc.

It becomes simple as in the given solution: Ip= I1*Z2/(Z1+Z2). As for the numerical calculation I assume a calculator can do the job for you.
 
Hesch said:
It seems that in the given solution another equivalent is used (T-equivalent) than the one in #1. It's hard to explain what happens in that other equivalent because I cannot see what is meant by Z1 and Z2.

Don't you like to calculate with complex numbers? I don't know if you find complex calculations "more efficient", but they will be more structured. Example:

Z0 = (Rc || jXm) = (560 || j800) = (375.8 + j263). That's it.

In the same way you calculate other impedances, that can be used in Kirchhoffs laws, etc.

It becomes simple as in the given solution: Ip= I1*Z2/(Z1+Z2). As for the numerical calculation I assume a calculator can do the job for you.

Hi,

Thanks for the reply.

I should have probably clarified that in this case,

Z1 = Rc // Xm

and

Z2 = X1eq + R1eq + a2ZL

I have no issues with complex numbers or the numerical computations; I suppose what I was referring to by 'efficient' was that in the original question, there was no value of Xm given (this was only given during the tutorial and seemed to be done off the cuff). This gave me the impression that the solution to this problem should have been different than the one given. Also, this was a 5-mark question and relative to other 5 mark questions, the given approach seemed like a lot of work.
 

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